Azure Classroomnotes 18/Jun/2023

Private Network vs Public Network

  • Public Network: A network which can be accessed from internet
  • Private Network: A network which cannot be accessed directly from internet.
  • For private networks there are some predefined or reserved cidr ranges
    Preview
  • CIDR Ranges
    • 10.0.0.0/8
    • 172.16.0.0/12
    • 192.168.0.0/16

Subnet

  • Network can be divided into multiple smaller networks called as subnets

Consider a building with 4 floors, we need to design a network

  • Each floor requires around 200 devices to be connected
  • Total building around 800 devices
    Preview
  • for building N = 22
building network cidr: 192.168.0.0/22

each floor N = 24

building SM: 11111111.11111111.11111100.00000000
floor SM:    11111111.11111111.11111111.00000000
            -------------------------------------
                                     xx
                                     00 => 192.168.0+(0).0/24
                                     01 => 192.168.0+(1).0/24
                                     10 => 192.168.0+(2).0/24
                                     11 => 192.168.0+(3).0/24
                                     192.168.0.0/24
                                     192.168.1.0/24
                                     192.168.2.0/24
                                     192.168.3.0/24
  • Each floor requires around 20000 devices to be connected
each floor ~= 20000
2^n ~= 20000
n = 15
N = 17

building ~= 80000
2^n ~= 80000
n = 17
N = 15

building => x.x.x.x/15 => 172.16.0.0/15

bd SM: 11111111.11111110.00000000.00000000
fl SM: 11111111.11111111.10000000.00000000
      ---------------------------------------
                       x.x    
                       0.0  => 172.(16+0).0.0/17 => 172.16.0.0/17
                       0.1  => 172.(16+0).128.0/17 => 172.16.128.0/17
                       1.0  => 172.(16+1).0.0/17 => 172.17.0.0/17
                       1.1  => 172.(16+1).128.0/17 => 172.17.128.0/17
  • Consider building has 8 floors, each floor requires 60 devices
floor ~= 60
2^n ~= 60
n = 6
N = 26

building = 480
2^n ~= 480
n = 9
N = 23
10.0.0.0/23


bd SM:  11111111.11111111.11111110.00000000
fl SM:  11111111.11111111.11111111.11000000
                         -------------------
                                 x.xx  
                                 0.00  => 10.0.0.0/26
                                 0.01  => 10.0.0.64/26
                                 0.10  => 10.0.0.128/26
                                 0.11  => 10.0.0.192/26
                                 1.00  => 10.0.1.0/26
                                 1.01  => 10.0.1.64/26
                                 1.10  => 10.0.1.128/26
                                 1.11  => 10.0.1.192/26
  • Consider a building with 8 floors and each floor requires 25000 devices
floor ~= 25000
2^n ~= 25000
n = 15
N = 17

building ~= 200000
2^n ~= 200000
n = 18
N = 14

10.0.0.0/14

bd SM: 11111111.11111100.00000000.00000000
fl SM: 11111111.11111111.10000000.00000000
       -------------------------------------
                      xx.x
                      00.0   => 10.0.0.0/17
                      00.1   => 10.0.128.0/17
                      01.0   => 10.1.0.0/17
                      01.1   => 10.1.128.0/17
                      10.0   => 10.2.0.0/17
                      10.1   => 10.2.128.0/17
                      11.0   => 10.3.0.0/17
                      11.1   => 10.3.128.0/17

Published
Categorized as Uncategorized Tagged

By continuous learner

devops & cloud enthusiastic learner

Leave a Reply

This site uses Akismet to reduce spam. Learn how your comment data is processed.

Please turn AdBlock off
Social Network Widget by Acurax Small Business Website Designers

Discover more from Direct DevOps from Quality Thought

Subscribe now to keep reading and get access to the full archive.

Continue reading

Visit Us On FacebookVisit Us On LinkedinVisit Us On Youtube