Design a Network with 6 subnets of size 300 each

• Solution:

subnets = 6

each subnet = 300
            ~= 512

6 * 512 = 3000

2^v ~=300 = 512 
v= 9
f = 32-9 = 23
10.0.0.0/8  172.16.0.0/12  192.168.0.0/16


Subnet  SM: 11111111.11111111.11111110.00000000
Network SM: 11111111.11111111.1111yyy0.00000000
ip:                      10.0.0000yyy0.0/23 
s1:                      10.0.00000000.0/23 = 10.0.0.0/23
ip:                      10.0.00000010.0/23 = 10.0.2.0/23
ip:                      10.0.00000100.0/23 = 10.0.4.0/23
                                              10.0.6.0/23
                                              10.0.8.0/23
                                              10.0.10.0/23

                            Network: 10.0.0.0/20

Design a Network with 8 subnets of size 400 each

• Solution

Subnets
10.0.0.0/23
10.0.2.0/23
10.0.4.0/23
10.0.6.0/23
10.0.8.0/23
10.0.10.0/23
10.0.12.0/23
10.0.14.0/23

Network:
10.0.0.0/20

Design a Network with 4 subnets of 1000 each

• Solution

2^ v ~= 1000
variable = 10
fixed = 22

subnets 4 = 2 bits

Subnet SM: 11111111.11111111.11111100.000000000
Net    SM: 11111111.11111111.1111yy00.000000000


ip: 192.168.0000yy00.0 

0100

s1: 192.168.0.0/22
s2: 192.168.4.0/22
s3: 192.168.8.0/22
s4: 192.168.12.0/22

N: 192.168.0.0/20

Design network with 5 subnets of size 1 lakh each

• Solution:

2^v ~= 1lakh

variable = 17
fixed = 15

priavte 10.0.0.0/8  192.168.0.0/16 172.16.0.0/12

Subnet SM: 11111111.11111110.00000000.00000000
                 10.0000yyy0.0.0/15

                 10.0.0.0/15
                 10.2.0.0/15
                 10.4.0.0/15
                 10.6.0.0/15
                 10.8.0.0/15

            Network: 10.0.0.0/12