Networking contd

Private CIDR Ranges

• 192.168.0.0/16
• 10.0.0.0/8
• 172.16.0.0/12

Scenario 3:

• Create a private network for 100000 devices

size = 100000

2^n - 2 ~= 100000
n = 17
N = 32 - 17 = 15

ip:        10.0000000x.xxxxxxxx.xxxxxxxx/15
sip:       10.00000000.00000000.00000000/15 => 10.0.0.0
eip:       10.00000001.11111111.11111111/15 => 10.1.255.255
SM:  11111111.11111110.00000000.00000000

range: 10.0.0.0 to 10.1.255.255

Subnetting

• Subnetting involves create subnetworks from network

Example -1

• In this case we need two subnets of size 500
  
• Network size and cidr

size = 1000
2^n ~= 1000
n = 10
N = 22

network cidr = 172.16.0.0/22
nsm: 11111111.11111111.11111100.00000000

• for subnet lets find network id bits and host id bits

2^n ~= 500
n = 9
N = 23

ssm: 11111111.11111111.11111110.00000000

• lets decide subnet ranges

ip:   172.16.0.0
nsm:  11111111.11111111.11111100.00000000
ssm:  11111111.11111111.11111110.00000000
      ------------------------------------
                              x
      -------------------------------------                        
ip:        172.16       .00000x0.0/23
s1:        172.16       .0000000.0/23 = 172.16.0.0/23
s2:        172.16       .0000010.0/23 = 172.16.2.0/23

Example -2

• Create a network for the following
  
• Network size = 4000

2^n ~= 4000
n = 12
N = 20

network: 10.0.0.0/20
nsm:  11111111.11111111.11110000.00000000

• subnet size = 1000

2^n ~= 1000
n = 10
N = 22
ssm:  11111111.11111111.11111100.00000000

• Lets find individual cidrs of subnet

nsm:  11111111.11111111.11110000.00000000
ssm:  11111111.11111111.11111100.00000000
ip:         10.       0.0000xx00.0/22 
s1:         10.       0.00000000.0/22 = 10.0.0.0/22
s2:         10.       0.00000100.0/22 = 10.0.4.0/22
s3:         10.       0.00001000.0/22 = 10.0.8.0/22 
s4:         10.       0.00001100.0/22 = 10.0.12.0/22

Example – 3

• Create a private network with subnet cidrs for the below
  
• Network: 192.168.0.0/21
• subnets:
  • 192.168.0.0/23
  • 192.168.2.0/23
  • 192.168.4.0/23
  • 192.168.6.0/23

Example -4

• Create a private network with 6 subnets of size 100 each
• network

2^n ~= 600
n = 10
N = 22

ip   192.168.0.0/22
nsm: 11111111.11111111.11111100.00000000

• subnet

2^n ~= 100
n = 7
N = 25

ssm: 11111111.11111111.11111111.10000000

• Subnet cidrs

nsm: 11111111.11111111.11111100.00000000
ssm: 11111111.11111111.11111111.10000000
ip:       192.     168.000000xx.x0000000/25
s1:       192.     168.00000000.00000000/25 = 192.168.0.0/25
s1:       192.     168.00000000.10000000/25 = 192.168.0.128/25
s1:       192.     168.00000001.00000000/25 = 192.168.1.0/25
s1:       192.     168.00000001.10000000/25 = 192.168.1.128/25
s1:       192.     168.00000010.00000000/25 = 192.168.2.0/25
s1:       192.     168.00000010.10000000/25 = 192.168.2.128/25

• Create a private network with
  • 16 subnets of 200 devices
  • 4 subnets of 50000 devices