MultiCloud Classroom notes 03/Jan/2025

Networking

Subnetting

  • Divding a larger network into multiple smaller networks

References

  • Private CIDR ranges
    • 192.168.0.0/16
    • 172.16.0.0/12
    • 10.0.0.0/8

Problem statement 1

  • I have to create two subnets for an organizational private network
  • Workplace will have 250 device and servers will be 250
  • Organizational network
total = 500

2^n - 2 ~= 500
n = 9
N = 32 - 9 = 23
network = 192.168.0.0/23
sip                                      = 192.168.0.0
eip            192.168.00000001.11111111 = 192.168.1.255
SM = 11111111.11111111.11111110.00000000
  • Subnet
size = 250
2^n - 2  ~= 250
n = 8
N = 24

N-SM: 11111111.11111111.11111110.00000000
S-SM: 11111111.11111111.11111111.00000000
           -------------------------------
                               X.
S1:             192.168.00000000.00000000/24 = 192.168.0.0/24
S2:             192.168.00000001.00000000/24 = 192.168.1.0/24  

Problem Statement 2

  • I have to create two subnets for an organizational private network
  • Workplace has 1000 devices and we have 1000 servers
  • Organization network size is 2000
2^n - 2 ~= 2000
n = 11
N = 32 - 11 = 21
ip: 10.200.0.0/21

SM:  11111111.11111111.11111000.00000000
  • Subnet
2^n - 2 ~= 1000
n = 10
N = 22


N-SM: 11111111.11111111.11111000.00000000
S-SM  11111111.11111111.11111100.00000000
         ----------------------------------
                             X
S1-IP:           10.200.00000000.00000000/22 = 10.200.0.0/22
S2-IP:           10.200.00000100.00000000/22 = 10.200.4.0/22

Problem Statement 3

  • Organization needs 4 subnets
  • Each subnet needs 2000 ip addresses
  • Organization size = 8000
2^n - 2 ~= 8000
n = 13
N = 32 -13 = 19

org-cidr = 172.16.0.0/19

SM:  11111111.11111111.11100000.00000000
  • Subnet
2^n -2 ~= 2000
n = 11
N = 32 - 11 = 21

NSM: 11111111.11111111.11100000.00000000
SSM: 11111111.11111111.11111000.00000000
-----------------------------------------
                          XX
S1ip:           172.16.00000000.0/21 = 172.16.0.0/21
S2ip:           172.16.00001000.0/21 = 172.16.8.0/21
S3ip:           172.16.00010000.0/21 = 172.16.16.0/21
S4ip:           172.16.00011000.0/21 = 172.16.24.0/21

Problem statement 4

  • Organization needs 4 subnets
  • Each subnet needs 100 devices
  • Organization size = 400
2^n - 2 ~= 400
n = 9
N = 32 - 9 = 23
ip: 192.168.0.0/23
NSM: 11111111.11111111.11111110.00000000
  • Subnet:
2^n -2 ~ = 100
n = 7
N = 25

NSM: 11111111.11111111.11111110.00000000
SSM: 11111111.11111111.11111111.10000000
------------------------------------------
                              X.X
S1ip:          192.168.00000000.00000000 = 192.168.0.0/25
S2ip:          192.168.00000000.10000000 = 192.168.0.128/25
S3ip:          192.168.00000001.00000000 = 192.168.1.0/25
S4ip:          192.168.00000001.10000000 = 192.168.1.128/25

Relevance of subnets with application architectures

  • Three tier architecture
  • Highly available three tier architecture

How to establish connectivity between two private networks

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By continuous learner

devops & cloud enthusiastic learner

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